Advertisements
Advertisements
Question
The value of a property decreases every year at the rate of 5%. If its value at the end of 3 years be Rs 44,540, what was the original value at the beginning of these 3 years?
Solution
Vn =Rs 44,540 ; V0 =? ; r = 5 % ; t = 3 years
`"V"_"n" = "V"_0 (1 - "r"/100)^"n"`
Rs 44540 = V0 `(1 - 5/100)^3`
V0 = Rs `44540 xx 100/95 xx 100/95 xx 100/95`
V0 = Rs 44, 540 x 1. 052632 x 1. 052632 x 1. 052632
V0 = Rs 51,949.26
The original value of the property was Rs 51,949.26
APPEARS IN
RELATED QUESTIONS
The simple interest on a certain sum in 2 years is Rs 1,300, whereas the compound interest on the same sum at the same rate and for the same time is Rs 1,365. Find the rate per cent and the sum.
Calculate the amount and the compound interest for the following:
Rs 20,000 for 2 years if the rates of interest are `12 1/4` and `5 1/2` for the successive years.
On what sum will the difference between compound interest and the simple interest for 2 years at `7 1/2` % be Rs 22.50 ?
The population of a town in the year 2005 was 4, 25,000. Find its population in the year 2007 if the rate of annual increase is 4% per year.
The population of a city is 1, 25,000. If the annual birth rate and death rate are 5.5% and 3.5% respectively, calculate the population of the city after 3 years.
In a factory the production of scooters rose to 46,305 from 40,000 in 3 years. Find the annual rate of growth of the production of scooters.
The present population of a town is 1, 15200.If it increases at the rate of `6 2/3`% per annum , find
Its population after 2 years
A machine was purchased 2 years ago. Its value decreases by 10% every year. Its present value is Rs 19,083.60. For how much money was the machine purchased?
The population of a city is 24,000. In the next 3 years it will be 27,783. Find the rate of growth of the population.
A new car is purchased for Rs 4, 00,000 .Its value depreciates at the rate of 10% per annum. What will be its value after 4 years?
