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The values of θ satisfying sin 7θ = sin4θ - sinθ and 0 < θ < π2 are ______ -

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Question

The values of θ satisfying sin7θ = sin4θ - sinθ and 0 < θ < `pi/2` are ______

Options

  • `pi/9, pi/4`

  • `pi/3, pi/9`

  • `pi/6, pi/9`

  • `pi/3, pi/4`

MCQ
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Solution

The values of θ satisfying sin 7θ = sin4θ - sinθ and 0 < θ < `pi/2` are `underline(pi/9, pi/4)`.

Explanation:

sin7θ = sin4θ - sinθ

⇒ sin7θ + sinθ - sin4θ = 0

⇒ 2sin4θ cos3θ - sin4θ = 0

⇒ sin4θ(2 cos3θ - 1) = 0

⇒ sin4θ = 0 or cos3θ = `1/2`

Now, sin4θ = 0 ⇒ 4θ = π ⇒ θ = `pi/4`

and cos3θ = `1/2` ⇒ 3θ = `pi/3` ⇒ θ = `pi/9`

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Linear Programming Problem (L.P.P.)
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