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Question
The volume of the greatest cylinder which can be inscribed in a cone of height 30 cm and semi-vertical angle 30° is ______.
Options
`(4000π)/(3 cm^3)`
`(400π)/(3 cm^3)`
`(4000π)/(sqrt(3) cm^3)`
None of these
MCQ
Fill in the Blanks
Solution
The volume of the greatest cylinder which can be inscribed in a cone of height 30 cm and semi-vertical angle 30° is `underlinebb((4000π)/(3 cm^3))`.
Explanation:
From geometry, we have `r/(30 tan 30^circ) = (30 - h)/30`
or h = `30 - sqrt(3)r`
Now, the volume of cylinder,
V = πr2h = `πr^2 (30 - sqrt(3)r)`
Now, let `(dV)/(dr)` = 0 or `π(60r - 3sqrt(3)r^2)` = 0
or r = `20/sqrt(3)`
Hence, Vmax = `π(20/sqrt(3))^2 (30 - sqrt(3) 20/sqrt(3))`
= `π 400/3 xx 10`
= `(4000π)/3`
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