Question

The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is ______.

Options

• `(4"RT")/"V"`

• `(88"RT")/"V"`

• `5/2 "RT"/"V"`

• `(3"RT")/"V"`

Answer 1

The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen, and 44 g of carbon dioxide at absolute temperature T. Consider R as the universal gas constant. The pressure of the mixture of gases is `bb(5/2 "RT"/"V")`.

Explanation:

Here we are using the ideal gas equation,

PV = nRT

n → total number of moles of the mixture of gases

No. of moles of O₂ : n₁ = `16/32` = 0.5 mole

No. of moles of N₂ : n₂ = `28/28`= 1 mole

No. of moles of CO₂ : n₃ = `44/44`= 1 mole

Total no. of moles in the container: n = n₁ + n₂ + n₃

n = 0.5 + 1 + 1 = `5/2` moles

P = `"nRT"/"V"`

∴ P = `5/2 "RT"/"V"`