Advertisements
Advertisements
Question
The wavelength of the vibrations produced on the surface of water is 2 cm. If the wave velocity is 16 ms-1, calculate:
- no. of waves produced in one second
- time required to produce one wave.
Solution
wavelength = λ = 2 cm = 0.02 m
Wave velocity = v = 16 ms-1
Frequency = f = ?
We know = v = λf
f = `"v"/lambda`
f = `16/0.02` = 800 Hz
⇒ 800 waves are produced in one second.
Time period = T = `1/"f"`
T = `1/800`
T = 0.00125s
APPEARS IN
RELATED QUESTIONS
An observer X is on an island 5500 m from a vertical cliff on the shore. A ship Y is anchored between the island and the Cliff. A blast on the ship’s siren is heard twice by X, the interval being 5s. [Velocity of sound = 330 ms−1]
(i) Find the distance of the ship from the island.
(i) Find the distance of the cliff from the ship.
Match the pairs.
Group ‘A’ | Group ‘B’ |
(a) Flute | (1) Frequency less than 20 Hz |
(b) Frequency | (2) Frequency more than 20000 Hz |
(c) Sound level | (3) Vibrations in the air |
(d) Ultrasonic sound | (4) Measured in Hz |
(e) Infrasonic sound | (5) Decibel |
A sound wave of wavelength 1/3 m has a frequency 996 Hz. Keeping the medium same, if frequency changes to 1328 Hz. Calculate
- velcoity of sound
- new wavelength.
How do the following factor affect the speed of sound in air?
Pressure in air.
What is the effect of temperature and pressure on the speed of sound in a gas?
The smoke from the gun barrel is seen 2 second before the explosion is heard. If the speed of sound in air is 350 ms-1, calculate the distance of observer from the gun.
The sound of which of the following frequency is audible to us?
2 Hz, 1000 Hz, 200 kHz, 8 MHz
Name the Sound of the Frequency Given Below:
200 Hz
Two sound waves X and Y have the same amplitude and the same wave pattern but their frequencies are 60 Hz and 120 Hz respectively, then ______.