Question

The work done by an applied variable force, F = x + x³ from x = 0 m to x = 2m, where x is displacement, is:

Options

• 6 J

• 8 J

• 10 J

• 12 J

Answer 1

6 J

Explanation:

W = `int "Fdx"`

W = `int_0^2 ("x" + "x" ^3) "dx"`

W = `["x"^2/2 + "x"^4/4]_0^2`

⇒ W = `[4/2 + 16/4] - [0 + 0]`

W = 6 J