Advertisements
Advertisements
Question
The work function of a metal is 4.2 eV. Its threshold wavelength will be ______.
Options
4000 Å
3500 Å
2959 Å
2500 Å
Solution
The work function of a metal is 4.2 Ev. Its threshold wavelength will be 2959 Å.
Explanation:
`lambda = (hc)/phi_0 = (6.63 xx 10^-34 xx 3 xx 10^8)/(4.2 xx 1.6 xx 10^-19`
= 2959.8 × 10−10
≈ 2959 Å
APPEARS IN
RELATED QUESTIONS
A photocell is used to automatically switch on the street lights in the evening when the sunlight is low in intensity. Thus it has to work with visible light. The material of the cathode of the photocell is ______.
If NRed and NBlue are the numbers of photons emitted by the respective sources of equal power and equal dimensions in unit time, then ______.
Choose the correct option.
The equation E = pc is valid ______.
Ultraviolet radiation of 6.2 eV falls on an aluminum surface (work function 4.2 eV). The kinetic energy in joules of the fastest electron emitted is ______
Define threshold frequency.
What is cut-off or stopping potential?
What is mean by the dual nature of matter?
Calculate the stopping potential when the metal with the work function 0.6 eV is illuminated with the light of 2 eV.