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Question
The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000 Å falls on it. The potential difference applied to stop the fastest photoelectrons is [h = 4.14 x 10-15 eV sec] ____________.
Options
1.2 volts
2.24 volts
3.6 volts
4.8 volts
MCQ
Fill in the Blanks
Solution
The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000 Å falls on it. The potential difference applied to stop the fastest photoelectrons is 1.2 volts.
Explanation:
`"Energy of incident light E" = 12375/2000`
`= 6.18 "eV"`
`"According to relation E" = phi + "eV"_0, "we get"`
`"V"_0 = (E - phi)/e `
`= ((6.18 e"V" - 5.01 e"V"))/e`
`1.17 "V" approx 1.2 "V"`
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The Photoelectric Effect
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