Question

The work of 146 kJ is performed in order to compress one-kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7 °C. The gas is ______.

(R = 8.3 J mol^-1 K^-1)

Options

• triatomic

• a mixture of monatomic and diatomic

• monatomic

• diatomic

Answer 1

The work of 146 kJ is performed in order to compress one-kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7 °C. The gas is a mixture of monatomic and diatomic.

Explanation:

In adiabatic process, `Delta` Q = 0

∴ work is done on the system `=>` internal energy of the system increases

∴ `Delta"U"  = Delta "W" => "n" xx "C"_"V" xx Delta "T" = Delta "w"`

∴ `"n" xx ("R")/((gamma-1)) xx 7 =146xx 10^3`

∴ `10^3 xx (8.3)/((gamma-1)) xx 7 =146xx 10^3`

∴ On solving we get, `gamma`= 1.

∴ The gas is diatomic.