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Question
There are ten boys B1, B2, ...., B10 and five girls G1, G2, ...., G5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B1 and B2 together should not be the members of a group is ______.
Options
1120
1130
1140
1150
MCQ
Fill in the Blanks
Solution
There are ten boys B1, B2, ...., B10 and five girls G1, G2, ...., G5 in a class. Then the number of ways of forming a group consisting of three boys and three girls, if both B1 and B2 together should not be the members of a group is 1120.
Explanation:
Let n(B) = 10
and n(g) = 5
The number of ways of forming a group of 3 girls of 3 boys.
= 5C3 × 10C3
= 80
Number of ways when boys B1 of B2 hot in the same group together
= 1200 × 80
= 1120
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