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Question
Three 2 Ω resistors, A, B and C, are connected as shown in Figure. Each of them dissipates energy and can withstand a maximum power of 18 W without melting. Find the maximum current that can flow through the three resistors?
Solution
P = I2R
where,
P = Potential difference
I = Current
R = Resistance
For resistor A,
18 = I2 × 2
`"I"^2= 18/2`
I2 = 9
I = 3A
This is the maximum current that can flow through the resistor A.
The maximum current flowing through the resistors B and C, `"I"^"'"=3×1/2 = 1.5 "A"`
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