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Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand, what is the minimum - Mathematics

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Question

Three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively. If a shopkeepeer wants to buy an equal number of biscuits, of each brand, what is the minimum number of packets of each brand, he should buy?

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Solution

A shopkeeper has three brands A, B and C of biscuits are available in packets of 12, 15 and 21 biscuits respectively.

Also, a shopkeeper wants to buy equal number of biscuits of each brand for that we need to find the LCM of 12, 15 and 21.

 2 
 12, 15, 21
 2
  6, 15, 21
 3
  3, 15, 21
 5
  1,  5,  7
 7
  1,  1,  7
 
  1,  1,  1

∴ The LCM of 12, 15 and 21 = 2 × 2 × 3 × 5 × 7 = 420 Thus, the required number of packets of 420.

Brand A = `420/12` = 35

Brand B = `420/15` = 28

Brand C = `420/21` = 20

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Chapter 1: Number System - Exercise [Page 20]

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NCERT Exemplar Mathematics [English] Class 6
Chapter 1 Number System
Exercise | Q 194 | Page 20

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