Question

Three numbers which are coprimes to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is

Options

• 75

• 81

• 85

• 89

Answer 1

85

Explanation:

Since, the numbers are coprimes, they contain only 1 as the common factor. Also, the given two products have the middle number in common.

So, middle number = HCF of 551 and 1073 = 29

So, first number = `(551/29)` = 19

Third number = `(1073/29)` = 37

∴ Required sum = 19 + 29 + 37 = 85