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Three randomly chosen non-negative integer x, y and z are found to satisfy the equation x + y + z = 10. Then, the probability that z is even, is ______. -

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Question

Three randomly chosen non-negative integer x, y and z are found to satisfy the equation x + y + z = 10. Then, the probability that z is even, is ______.

Options

  • 1/2

  • 36/55

  • 6/11

  • 5/11

MCQ
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Solution

Three randomly chosen non-negative integer x, y and z are found to satisfy the equation x + y + z = 10. Then, the probability that z is even, is 6/11.

Explanation:

∵ Sample space = 12C2

Number of possibilities for z is even,

z = 0 `\implies` 11C1

z = 2 `\implies` 9C1

z = 4 `\implies` 7C1

z = 6 `\implies` 5C1

z = 8 `\implies` 3C1

z = 10 `\implies` 1C

Total possibilities = 36

∴ Required probability = 36/66 = 6/11

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