Advertisements
Advertisements
Question
\[\begin{array}{cc}
\phantom{......................................................}\ce{CH3}\phantom{............}\ce{Br}\phantom{}\\
\phantom{....................................................}|\phantom{.............}/\phantom{}\\
\ce{A + Mg ->[Dry][ether] CH3-Mg-Br + B ->[i. Dry ether][ii. H-OH/H^+] CH3-C-OH + Mg}\\
\phantom{.....................................................}|\phantom{.............}\backslash\phantom{}\\
\phantom{......................................................}\ce{CH3}\phantom{..........}\ce{OH}\phantom{}
\end{array}\]
Thus, 'B' in the above reaction is:
Options
propionaldehyde
propanone
propionic acid
propanenitrile
MCQ
Solution
propanone
Explanation:
shaalaa.com
Alkenes
Is there an error in this question or solution?
