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Two Balls, a (Mass 3kg) and B (Mass 4kg), Are Moving with Velocities 25 M/S and 40 M/S Respectively (Refer Figure 15). before Impact, the Direction of Velocity of Two Balls Are 300 and 500 with the L - Engineering Mechanics

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Question

Two balls, A (mass 3kg) and B (mass 4kg), are moving with velocities 25 m/s and 40 m/s respectively (Refer Figure 15). Before impact, the direction of velocity of two balls are 300 and 500 with the line joining their centers as shown in Figure 15. If coefficient of restitution for the impact is 0.78, find the magnitude and the direction of velocities of the balls after the impact.

Answer in Brief

Solution

uAx = 25sin(30) = 12.5 m/s
uAy = 25cos(30) = 21.65 m/s
uBx = 40sin(50) = 30.64 m/s
uBy = -40cos(50) = -25.71 m/s
Momentum is conserved only along the line of action.
mAuAy + mBuBy = mAvAy + mBuBy
3(21.65) + 4(-25.71) = 3vAy + 4vBy

3vAy + 4vBy = -37.89 …..(1)

`e = (VBy-V)/(UAy-UBy)`

`0.78 = (VBy - VAy)/(21.65+25.71`

vBy – vAy = 36.9408 …..(2)
Solving (1) and (2)

vAy = -26.52 m/s = 26.52 m/s↓

vBy = 10.42 m/s↑

The magnitude of the velocities and direction of A and B are 26.52 m/s downwards and 10.42 m/s upwards respectively.

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Velocity and Acceleration in Terms of Rectangular Co-ordinate System
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