Advertisements
Advertisements
Question
Solution
We know that R = `"V"^2/"P"`
`"Resistance of 60 W-220 V bulb"/"Resistance of 60 W-220 V bulb" = (220)^2/60 x 60/(110)^2 = 4/1`
Thus, the required ratio is 4: 1.
APPEARS IN
RELATED QUESTIONS
An electric heater is rated at 2 kW. Electrical energy costs Rs 4 per kWh. What is the cost of using the heater for 3 hours?
(a) Rs 12
(b) Rs 24
(c) Rs 36
(d) Rs 48
What is the energy conversion when an electric current passes through a metallic wire?
State the position of heating element with respect to principal focus of concave reflector and give reason for choosing this position.
The electric bulbs used these days have a coil-coiled filament. State its reason.
Why does not the heating coil produce any visible light? in an electric stove.
What is the order of current drawn by appliances connected to the ‘power circuit’ of a household?
State other bigger units of electric power and express them in watt.
A bulb is connected to a battery of e.m.f. 6V and internal resistance 2Ω A steady current of 0.5A flows through the bulb. Calculate the resistance of the bulb.
1 kWh is equal to:
Using a long extension cord in which each conductor has a resistance of 8Ω, a bulb marked as '100 W, 200 V' is connected to a 220 V dc supply of negligible internal resistance as shown in the figure. The power delivered to the bulb is ______ W.