Question

Two cards are drawn together from a pack of 52 cards. The probability that one is a club and one is a diamond, is

Options

• `13/102`

• `46/104`

• `12/21`

• `13/200`

Answer 1

`13/102`

Explanation:

Probability of club card = `""^13C_1`

Probability of diamond card = `""^13C_1`

E = event of getting 1 club and 1 diamond card

Total = N(S) = `""^52C_2`

`=(52 xx 51)/(2 xx 1) = 1326`

P(E) = `("N"("S"))/("N"("S")) = (""^13C_1 xx ""^13C_1)/1326 = 13/102`