Question

Two charge – 10c and + 10 c are placed 10 cm apart. Potential at centre of the line joining the two charge is:-

Options

• Zero

• 2V

• – 2V

• None of these

Answer 1

Zero

Explanation:

V  = `1/(4piε_0r) (q_1+ q_2)`

= `(9 xx 10^9)/(5 xx 10^-2) (-10 + 10)` = zero.