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Question
Two equal forces acting at a point with an angle of 60° between them, if the resultant is equal `30sqrt(3)N`, the magnitude of the force will be
Options
20 N
0
30 N
60 N
MCQ
Solution
30 N
Explanation:
Given, F1 = F2 = F ......(Say)
R = `30sqrt(3)` N and θ = 60°
The resultant force on the body.
R = `sqrt(F_1^2 + F_2^2 + 2F_1F_2 cos theta)`
`30sqrt(3) = sqrt(F^2 + F^2 + 2F^2 cos 60^circ)`
= `sqrt(2F^2 + 2F^2 xx 1/2)`
`30sqrt(3) = sqrt(3F^2) = sqrt(3)F`
F = 30 N = F1 = F2.
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Magnitude and Direction of a Vector
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