Question

Two identical thin metal plates has charge q₁ and q₂ respectively such that q₁ > q₂. The plates were brought close to each other to form a parallel plate capacitor of capacitance C. The potential difference between them is ______.

Options

• `(("q"_1+"q"_2))/"C"`

• `(("q"_1-"q"_2))/"C"`

• `(("q"_1-"q"_2))/(2"C")`

• `(2("q"_1-"q"_2))/"C"`

Answer 1

Two identical thin metal plates has charge q₁ and q₂ respectively such that q₁ > q₂. The plates were brought close to each other to form a parallel plate capacitor of capacitance C. The potential difference between them is `underlinebb((("q"_1-"q"_2))/(2"C"))`.

Explanation:

Electric field between plates given by,

E = `("q"_1-"q"_2)/(2"A"epsilon_0)`

(Here, q₁ > q₂)

Then, the potential difference will be

V = Ed = `("q"_1-"q"_2)/(2"A"epsilon_0)`d = `("q"_1-"q"_2)/(2"C")`       `(∵ "C" = (epsilon_0"A")/"d" )`