Question

Two monoatomic gas A and B occupying the same volume V are at the same temperature T and pressure P. If they are mixed, the resulting mixture has volume V and temperature T. The pressure of the mixture is:

Options

• P

• `"P"/2`

• 4P

• 2P

Answer 1

2P

Explanation:

`("P"_1"V"_1)/"T"_1 = ("P"_"mix" "V"_"mix")/"T"_"mix"`

T₁ = T_mix = T and V₁ = V + V, V_mix = V

`("P"(2"V"))/"T" = ("P"_"mix" "V")/"T"`

P_mix = 2P