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Question
Two open pipes of different lengths and same diameter in which the air column vibrates with fundamental frequencies 'n1', and 'n2' respectively. When both pipes are joined to form a single pipe, its fundamental frequency will be ______.
Options
`("n"_1 + "n"_2)/("n"_1"n"_2)`
`("n"_1"n"_2)/(2"n"_2 + "n"_1)`
`(2"n"_2 + "n"_1)/("n"_1"n"_2)`
`("n"_1"n"_2)/("n"_1 + "n"_2)`
Solution
Two open pipes of different lengths and same diameter in which the air column vibrates with fundamental frequencies 'n1', and 'n2' respectively. When both pipes are joined to form a single pipe, its fundamental frequency will be `underlinebb(("n"_1"n"_2)/("n"_1 + "n"_2))`.
Explanation:
For open pipe with frequency n1 and length l1,
`"n"_1 = v/(2"l"_1) => "l"_1 = "v"/(2"n"_1)` ...(i)
Similarly, for open pipe with frequency n2 and length l2,
`"n"_2 = v/(2"l"_2) => "l"_2 = "v"/(2"n"_2)` ...(ii)
When both the pipes are joined together then net length of the pipe will be,
L = l1 + l2 ...(iii)
Let, after joining the pipes fundamental frequency will be N0,
So, L = `"v"/(2"N"_0) = l_1 + l_2`
⇒ L = `"v"/(2"n"_1) + "v"/(2"n"_2) = "v"/(2"N"_0)`
Using Eqs. (i) and (Ii), we get
`=> "N"_0 = ("n"_1"n"_2)/("n"_1 + "n"_2)`