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Question
Two parallel conducting wires of equal lengths placed distance 'd' apart carry currents 'I1' and 'I2' respectively in opposite directions. The resultant magnetic field at the midpoint of both the wires is ______.
(µ0 = permeability of free space.)
Options
`µ_0 ("I"_1 + "I"_2) //pi"d"`
`µ_0 ("I"_1 + "I"_2) //2pi"d"`
`µ_0 ("I"_1 - "I"_2) //2pi"d"`
`µ_0 ("I"_1 - "I"_2) //pi"d"`
Solution
Two parallel conducting wires of equal lengths placed distance 'd' apart carry currents 'I1' and 'I2' respectively in opposite directions. The resultant magnetic field at the midpoint of both the wires is `underline( µ_0 ("I"_1 + "I"_2) //pi"d")`
Explanation:
Field due to a current-carrying long wire is given by
B =`(µ_"0""I")/(2pi"r")`
To fields at the midpoint between the two wires are in the same direction and hence get added.
The distance of the midpoint r = `"d"/2`
`therefore "B" ="B"_1 + "B"_2 = (µ_"0""I"_1)/(2pi("d"/2)) + (µ_"0""I"_2)/(2pi("d"/2))`
` = (µ_"0"("I"_1 + "I"_2))/(pi"d")`