Advertisements
Advertisements
Question
Two parallel plates separated by a distance 'd' are kept at potential difference 'V' volt. A charge 'q' of mass 'm' enters in parallel plates with some velocity. The acceleration of the charged particle will be ______
Options
`(qd)/(Vm)`
`(qV)/(dm)`
`(md)/(Vg)`
`(qm)/(Vd)`
MCQ
Fill in the Blanks
Solution
Two parallel plates separated by a distance 'd' are kept at potential difference 'V' volt. A charge 'q' of mass 'm' enters in parallel plates with some velocity. The acceleration of the charged particle will be `underline((qV)/(dm))`.
Explanation:
E = `V/d`
Force on the charge = qE = `q V/d`
Acceleration = `(qE)/m = (qV)/(dm)`
shaalaa.com
Electric Potential and Potential Energy
Is there an error in this question or solution?
