Question

Two parallel plates separated by 'd' mm are kept at potential difference of 'V' volt. A particle of mass 'm' and charge 'q' enters in it with some velocity. The acceleration of the particle will be ______.

Options

• ${\displaystyle \frac{qV}{dm}}$

• ${\displaystyle \frac{qd}{Vm}}$

• ${\displaystyle \frac{qm}{Vd}}$

• ${\displaystyle \frac{q}{dmV}}$

Answer 1

Two parallel plates separated by 'd' mm are kept at potential difference of 'V' volt. A particle of mass 'm' and charge 'q' enters in it with some velocity. The acceleration of the particle will be ${\displaystyle \underline{\frac{qV}{dm}}}$.

Explanation:

Electric field between the plates ${\displaystyle E=\frac{V}{d}}$

Force on charge q : F = qE = ${\displaystyle \frac{qV}{d}}$

Acceleration a : ${\displaystyle a=\frac{F}{m}=\frac{qV}{dm}}$