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Two particles A and B have equal charges but different masses MA and M8. After being accelerated through same potential difference enter the region of uniform magnetic field -

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Question

Two particles A and B have equal charges but different masses MA and M8. After being accelerated through same potential difference enter the region of uniform magnetic field and describe the path of radii RA and RB respectively. Then MA : MB is ______.

Options

  • `"R"_"B"/"R"_"A"`

  • `("R"_"A"/"R"_"B")^2`

  • `"R"_"A"/"R"_"B"`

  • `("R"_"B"/"R"_"A")^2`

MCQ
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Solution

Two particles A and B have equal charges but different masses MA and M8. After being accelerated through same potential difference enter the region of uniform magnetic field and describe the path of radii RA and RB respectively. Then MA : MB is `underline(("R"_"A"/"R"_"B")^2)`.

Explanation:

Since the two particles have same charge and are accelerated through the same potential difference, they have same kinetic energy k(=qV). Ifp is the momentum then

k = `"P"^2/"2m" or "P" = sqrt"2mk"`.

The radius of the circular path in a magnetic field is given by

R = `"p"/"qB" = sqrt"2mk"/"qB"`

`therefore "R" prop sqrt"m"`

or `"M"_"A"/"M"_"B" = "R"_"A"^2/"R"_"B"^2`

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