Question

Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational force of attraction. The speed of each particle is (M = mass of the particle) ____________.

Options

• `sqrt("GM"/R)`

• `1/2 sqrt("GM"/R)`

• `1/3 sqrt("GM"/R)`

• `1/4 sqrt("GM"/R)`

Answer 1

Two particles of equal mass go around a circle of radius R under the action of their mutual gravitational force of attraction. The speed of each particle is (M = mass of the particle)

`1/2sqrt("GM"/R)`.

Explanation:

`(GM^2)/(2R)^2 = (Mv^2)/R or (GM)/(4R) = v^2 or v = 1/2 sqrt("GM"/R)`