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Question
Two pith balls, each of mass 1.8 g, are suspended from the same point by silk threads each of length 20 cm. When equal charge Q is given to both the balls, they separate until the two threads become perpendicular. Then the charge Q on each pith ball is ______.
Note: `[1/(4piepsilon_0) = 9 xx 10^9)]`nm2/c2
Options
2 × 10-7 C
3 × 10-7 C
4 × 10-7 C
5 × 10-7 C
Solution
Two pith balls, each of mass 1.8 g, are suspended from the same point by silk threads each of length 20 cm. When equal charge Q is given to both the balls, they separate until the two threads become perpendicular. Then the charge Q on each pith ball is 4 × 10-7 C.
Explanation:
T cos 45 = mg ...(i)
T sin 45 = `"kq"^2/"mgr"^2` ...(ii)
(r = 2 l sin 45°) & k = 9 × 109
From (i) & (ii)
`tan 45^circ = "kq"^2/"mgr"^2`
`=> "q" = sqrt("mg r"^2 tan 45^circ)/"k"`
putting values of m, g, k, r we get q = 4 × 10-7 C