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Two planets A and B of equal mass are having their period of revolutions TA and TB such that TA = 2TB. These planets are revolving in the circular orbits of radii rA and rB respectively. -

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Question

Two planets A and B of equal mass are having their period of revolutions TA and TB such that TA = 2TB. These planets are revolving in the circular orbits of radii rA and rB respectively. Which out of the following would be the correct relationship of their orbits?

Options

  • `2"r"_"A"^2="r"_"B"^2`

  • `"r"_"A"^3=2"r"_"B"^3`

  • `"r"_"A"^3=4"r"_"B"^3`

  • `"T"_"A"^2-"T"_"B"^2=pi^2/"GM"("r"_"B"^3-4"r"_"A"^3)`

MCQ

Solution

`bb("r"_"A"^3=4"r"_"B"^3)`

Explanation:

By kepler's law T2 ∝ r3

⇒ `("T"_"A"/"T"_"B")^2=("r"_"A"/"r"_"B")^3`

⇒ 22 = `("r"_"A"/"r"_"B")^3` 

⇒ `"r"_"A"^3=4"r"_"B"^3`

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