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Question
Two-point charges +8q and -2q are located at x = 0 and x = L respectively. The point on x-axis at which the net electric field is zero due to these charges is - ____________.
Options
8L
4L
2L
L
Solution
Two-point charges +8q and -2q are located at x = 0 and x = L respectively. The point on the x-axis at which the net electric field is zero due to these charges is - 2L.
Explanation:
Let P is the observation point at a distance r from -2q and at (L+r) from +8q.
Given Now, Net EFI at P = 0
`therefore vec"E"_1` = EFI (Electric Field Intensity) at P due to +8q
`vec"E"_2` = EFI (Electric Field Intensity) at P due to -2q
`abs(vec"E"_1) = abs(vec"E"_2)`
`therefore ("k" (8"q"))/("L + r")^2 = ("k" (2 "q"))/"r"^2`
`therefore 4/("L + r")^2 = 1/("r")^2`
`4"r"^2 = ("L + r")^2`
`2"r" = "L + r"`
r = L
`therefore` P is at x = L + L = 2L from origin
`therefore` Correct Option is (iii) 2L