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Question
Two rectangular blocks A and B of different metals have same length and same area of cross-section. They are kept in such a way that their cross-sectional area touch each other. The temperature at one end of A is 100°C and that of B at the other end is 0°C. If the ratio of their thermal conductivity is 1 : 3, then under steady state, the temperature of the junction in contact will be ______.
Options
25°C
50°C
75°C
100°C
Solution
Two rectangular blocks A and B of different metals have same length and same area of cross-section. They are kept in such a way that their cross-sectional area touch each other. The temperature at one end of A is 100°C and that of B at the other end is 0°C. If the ratio of their thermal conductivity is 1 : 3, then under steady state, the temperature of the junction in contact will be 25°C.
Explanation:
`R_A = L/(K_1a)`
`R_B = L/(K_2a)`
Where a is the cross sectional area of the rod and L is the length of the rod and K1 and K2 are the thermal conductivity of each rod.
`T_J = R_B/(R_A + R_B)(100 - 0)`
= `1/((R_A)/(R_B) + 1) xx 100`
= `100/(3 + 1)`
= 25°C