Question

Two slits, 4mm apart, are illuminated by light of wavelength 6000 A° what will be the fringe width on a screen placed 2 m from the slits?

Options

• 0.12 mm

• 0.3 mm

• 3.0 mm

• 4.0 mm

Answer 1

0.3 mm

Explanation:

`beta =  = (lambdaD)/d`

= `(6000 xx 10^-10 xx 2)/(4 xx 10^-3)`

= `3 xx 10^-4` m

= 0.3 mm