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Two spherical black bodies of radius r1 and r2 with surface temperature T1 and T2 respectively, radiate same power, then r1 : r2 is ______. -

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Question

Two spherical black bodies of radius r1 and r2 with surface temperature T1 and T2 respectively, radiate same power, then r1 : r2 is ______.

Options

  • `("T"_2/"T"_1)^4`

  • `("T"_2/"T"_1)^2`

  • `("T"_1/"T"_2)^2`

  • `("T"_1/"T"_2)^4`

MCQ
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Solution

Two spherical black bodies of radius r1 and r2 with surface temperature T1 and T2 respectively, radiate same power, then r1 : r2 is `underline(("T"_2/"T"_1)^2)`.

Explanation:

The power radiated by the black body,

E = εσAT4

It is given that, both spherical bodies radiate same power.

∴ E1 = E2

`"T"_1^4 "r"_1^2 = "T"_2^4 "r"_2^2` (for spherical body, A = 4πr2)

`=> "r"_1/"r"_2 = ("T"_2/"T"_1)^2`

OR

`4pi_1^2"T"_1^4 = 4pi"r"_2^2"T"_2^4`

`"R"_1^2/"r"_2^2 = "T"_2^4/"T"_1^4`

`"r"_1/"r"_2 = "T"_2^2/"T"_1^2`

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Spectral Distribution of Blackbody Radiation
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