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Question
Two spherical blackbodies have radii 'r1' and 'r2'. Their surface temperature are 'T1' and 'T2'. If they radiate same power, then `"r"_2/"r"_1` is ________.
Options
`"T"_1/"T"_2`
`"T"_2/"T"_1`
`("T"_1/"T"_2)^2`
`("T"_2/"T"_1)^2`
MCQ
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Solution
Two spherical blackbodies have radii 'r1' and 'r2'. Their surface temperature are 'T1' and 'T2'. If they radiate same power, then `"r"_2/"r"_1` is `("T"_1/"T"_2)^2`.
Explanation:
`"For blackbody, P" = "A"epsilonsigma"T"^4`
`"For same power, A" prop 1/"T"^4`
`therefore ("r"_1/"r"_2)^2 = ("T"_2/"T"_1)^4`
`therefore "r"_1/"r"_2 = ("T"_2/"T"_1)^2 "i.e.," "r"_2/"r"_1 = ("T"_1/"T"_2)^2`
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Stefan-boltzmann Law of Radiation
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