Question

Two springs of spring constants 'K' and '2K' are stretched by same force. If 'E₁' and 'E₂' are the potential energies stored in them respectively, then ______.

Options

• `"E"_1=1/4"E"_2`

• E₁ = 2E₂

• E₂ = 2E₁

• E₁ = E₂

Answer 1

Two springs of spring constants 'K' and '2K' are stretched by same force. If 'E₁' and 'E₂' are the potential energies stored in them respectively, then ______.

Explanation:

F = kx₁ = (2k)x₂

∴ kx₁ = 2kx₂

x₁ = 2x₂

`E_1=1/2"kx"_1^2`

`E_2=1/2(2"k")x_2^2=1/2(2"k")x_1^2/4`

`thereforeE_1/E_2=(1/2"kx"_1^2)/(1/4"kx"_1^2)=2`

E₁ = 2E₂