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Two unknown resistances are connected in two gaps of a meter-bridge. The null point is obtained at 40 cm from left end. A 30 Ω resistance is connected in series -

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Question

Two unknown resistances are connected in two gaps of a meter-bridge. The null point is obtained at 40 cm from left end. A 30 Ω resistance is connected in series with the smaller of the two resistances, the null point shifts by 20 cm to the right end. The value of smaller resistance Ω is ______.

Options

  • 12

  • 24

  • 36 

  • 48

MCQ
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Solution

Two unknown resistances are connected in two gaps of a meter-bridge. The null point is obtained at 40 cm from left end. A 30 Ω resistance is connected in series with the smaller of the two resistances, the null point shifts by 20 cm to the right end. The value of smaller resistance Ω is 24.

Explanation:

From question, 1X = 40cm, IR = 60cm.

using principle of metre-bridge,

`"X"/"R"="I"_"X"/"I"_"R"=40/60=2/3`        ...(i)

When 30Ω resistance is connected in series with the smaller of the two resistances

`("X"+30)/"R"=60/40=3/2`

⇒ R = `(2("X"+30))/3`          ...(ii)

From eqs. (i) and (ii),

`"X"/(2(("X"+30)/3))=2/3`

 ⇒ `(3"X")/(2("X"+30))=2/3`

or, 9X = 4X + 120 ⇒ 5X = 120

∴ X = 24Ω

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