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Use a Method of Your Own Choice to Find the H.C.F. of 24, 36, 60 and 132. - Mathematics

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Question

Use a method of your own choice to find the H.C.F. of 24, 36, 60, and 132.

Sum

Solution

Factor of 24 = F24 = 2 x 2 x 2 x 3
Factor of 36 = F36 = 2 x 2 x 3 x 3
Factor of 60 = F60 = 2 x 2 x 3 x 5
and Factor of 132 = F132 = 2 x 2 x 3 x 11
Now the common factors of 24, 36, 60 and 132 = 2, 2 and 3
H.C.F. = 2 x 2 x 3 = 12

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Concept for HCF and LCM
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Chapter 8: HCF and LCM - Exercise 8 (B)

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Selina Mathematics [English] Class 6
Chapter 8 HCF and LCM
Exercise 8 (B) | Q 4.4
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