Question

Using repeated division method, find the HCF of the following:

455 and 26

Answer 1

Step 1: The larger number should be dividend 455 and smaller number should be divisor = 26

Step 2: After 1^st division, the remainder becomes new divisor and the previous divisor becomes next dividend.

Step 3: This is done till remainder is zero.

Step 4: The last divisor of the HCF is 13.

∴ HCF = 13