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Maharashtra State BoardSSC (English Medium) 6th Standard

Using the figures given below, frame problems based on profit percent or loss percent. Cost price ₹1600, selling price ₹ 2800 - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Using the figures given below, frame problems based on profit percent or loss percent.

Cost price ₹1600, selling price ₹ 2800

Sum

Solution

Problem: A man bought an article for Rs 1600 and sold it for Rs 2800. Find his profit percent.

Cost price of an article = Rs 1600

Selling price of an article = Rs 2800

Since selling price is more than cost price, so there is a profit.

Profit = Selling Price − Cost Price

= 2800 − 1600

= Rs 1200

Let x % be the profit made by the man in this transaction. Then,

`"x"/100 = "profit"/"cost price" = 1200/1600`

`=> "x"/100 xx 100 = 1200/1600 xx 100`

⇒ x = 75

∴ The man made a profit of 75% in this transaction.

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Chapter 13: Profit – Loss - Practice Set 34 [Page 72]

APPEARS IN

Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 13 Profit – Loss
Practice Set 34 | Q 1 | Page 72
Balbharati Integrated 6 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.4 Profit-Loss
Practice Set 34 | Q 1. | Page 67

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