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Question
Using the rule of negation write the negation of the following with justification.
p → (p ∨ ∼ q)
Solution
The negation of p → (p ∨ ∼ q) is ∼ [p → (p ∨ ∼ q)] ≡ p ∧ ∼ (p ∨ ∼ q) .......(Negation of implication)
≡ p ∧ [∼ p ∧ ∼ (∼ q)] .....(Negation of disjunction)
≡ p ∧ (∼ p ∧ q) .......(Negation of negation)
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