Advertisements
Advertisements
Question
Verify that the following is an AP, and then write its next three terms.
`5, 14/3, 13/3, 4,...`
Solution
Here,
a1 = 5
a2 = `14/3`
a3 = `13/3`
a4 = 4
a2 – a1 = `14/3 - 5`
= `(14 - 15)/3`
= `(-1)/3`
a3 – a2 = `13/3 - 14/3`
= `-1/3`
a4 – a3 = `4 - 13/3`
= `(12 - 13)/3`
= `(-1)/3`
Since, difference of successive terms are equal,
Hence `5, 14/3, 13/3, 4,...` is an AP with common difference `-1/3`
Therefore, the next three term will be,
a5 = a1 + 4d
= `5 + 4(-1/3)`
= `5 - 4/3`
= `11/3`
a6 = a1 + 5d
= `5 + 5(-1/3)`
= `5 - 5/3`
= `10/3`
a7 = a1 + 6d
= `5 + 6(-1/3)`
= 5 – 2
= 3
APPEARS IN
RELATED QUESTIONS
Which term of the sequence 4, 9 , 14, 19, …… is 124 ?
Four numbers are in A.P. If their sum is 20 and the sum of their square is 120, then find the middle terms
For the following arithmetic progressions write the first term a and the common difference d:
`1/5, 3/5, 5/5, 7/5`
The general term of a sequence is given by an = −4n + 15. Is the sequence an A.P.? If so, find its 15th term and the common difference.
How many terms are there in the A.P.?
7, 10, 13, ... 43.
If nine times ninth term is equal to the fifteen times fifteenth term, show that six times twenty fourth term is zero
Choose the correct alternative answer for the following sub question.
In an Arithmetic Progression 2, 4, 6, 8, ... the common difference d is ______
1, 6, 11, 16 ...... Find the 18th term of this A.P.
Justify whether it is true to say that `-1, - 3/2, -2, 5/2,...` forms an AP as a2 – a1 = a3 – a2.
The first term of an A.P. is 22, the last term is –6 and the sum of all the terms is 64. Find the number of terms of the A.P. Also, find the common difference.
