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विस्तार करा. (4 − p)3 - Mathematics [गणित]

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Question

विस्तार करा.

(4 − p)

Sum

Solution

(4 − p)

(a − b)3 = a3 − 3a2b + 3ab2 − b3

= `(4)^3 - 3 xx (4)^2 (p) + 3 xx 4 xx(p)^2 - (p)^3`

= `64 - 3 xx 16 xx p + 12p^2 - p^3`

= `64 - 48p + 12p^2 - p^3`

(4 − p)3 = `64 - 48p + 12p^2 - p^3`

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Chapter 3.5: विस्तार सूत्रे - सरावसंच 5.3 [Page 79]

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Balbharati Integrated 8 Standard Part 1 [Marathi Medium] Maharashtra State Board
Chapter 3.5 विस्तार सूत्रे
सरावसंच 5.3 | Q 1. (2) | Page 79
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