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We know that the relationship between Kc and Kp is Kp = Kc (RT)∆n What would be the value of ∆n for the reaction NHX4Cl(s)↽−−⇀NHX3(g)+HCl(g) - Chemistry

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Question

We know that the relationship between Kc and Kp is Kp = Kc (RT)∆n What would be the value of ∆n for the reaction \[\ce{NH4Cl (s) ⇌ NH3 (g) + HCl (g)}\]

Options

  • 1

  • 0.5

  • 1.5

  • 2

MCQ

Solution

2

Explanation:

The relationship between Kp and Kc is Kp = Kc (RT)n

Where ∆n = (Number of moles of gaseous products) – (Number of moles of gaseous reactants)

For the reaction,

\[\ce{NH4Cl (s) ⇌ NH3 (g) + HCl (g)}\]

∆n = 2 – 0 = 2

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Homogeneous Equlibria - Equilibrium Constant in Gaseous Systems
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Chapter 7: Equilibrium - Multiple Choice Questions (Type - I) [Page 86]

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NCERT Exemplar Chemistry [English] Class 11
Chapter 7 Equilibrium
Multiple Choice Questions (Type - I) | Q 1 | Page 86
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