Question

What is the rate constant of a first order reaction if 0.08 mole of reactant reduces to 0.02 mole in 23.03 minutes?

Options

• 1.6021 min^-1

• 0.2303 min^-1

• 0.4031 min^-1

• 0.06021 min^-1

Answer 1

0.06021 min^-1 

Explanation:

For first order reactions,

t = `2.303/"k" log "a"/("a - x")`

where, t = time, k = rate constant

a = initial concentration

a - x = remaining concentration

`=> k = 2.303/23.03 log  0.08/0.02`

k `= 1/10 log 4`

 k `= 0.6020/10`

k= 0.06020 min^-1