Question

What is the amount of water formed by the combustion of 1.6 g methane?

Options

• 3.6 g

• 3.2 g

• 16 g

• 6.2 g

Answer 1

3.6 g

Explanation:

The reaction involves the combustion of methane is as follows

\[\ce{\underset{(16 g)}{CH4(g)} + 2O2(g) -> CO2(g) + \underset{(2 × 15 g)}{2H2O(g)}}\]

In this reaction, 1 mol of CH₄ gives → 2 moles of water

16 g of CH₄ gives → 2 × 18 g = 36 g

So, 1.6 g of CH₄ gives = `36/16 xx 1.6 = 3.6` g water