Question

What is the angular momentum of the electron in the third Bohr orbit in the hydrogen atom? [Given: `h/(2π) = 1.055 xx 10^-34 kg.m^2//s`]

Answer 1

Angular momentum, L = `mvr = (nh)/(2π)`

For n = 3, L = 3 `(h/(2π))`

= 3 (1.055 × 10⁻³⁴)

= 3.165 × 10⁻³⁴ KG.m²/s