Question

What is the bona order of O₂ molecules?

Options

• 1

• 1.5

• 2.0

• 3.5

Answer 1

2.0

Explanation:

The electronic configuration of O₂ molecule is as

`sigma 1"s"^2, sigma^• 1s^2, sigma 2"s"^2, sigma^• 2"s"^2, sigma^•"2p"_"z"^2, pi 2"p"_x^2 = pi2"p"_"y"^2, pi^•2"p"_x^1 = pi^• 2"p"_"y"^1`.

Bond order = `("N"_"b" - "N"_"a")/2`

`= (10 - 6)/2`

`= 4/2`

= 2