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Question
What is the energy required to built up a current of lA in an inductor of 20 mH?
Numerical
Solution
`E = 1/2 LI^2`
`E = 1/2 xx 20 xx 10^-3 xx (1)^2`
`1/2 xx 20 xx 10^-3 J =10^-2 J`
E = 10 mJ
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Energy Stored in a Magnetic Field
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