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What is the molecularity and order of the following reaction if rate law is, rate = k [O3][O] respectively OX3(g)+OX(g)⟶2OX2(g) -

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Question

What is the molecularity and order of the following reaction if rate law is, rate = k[O3][O] respectively.

\[\ce{O_{3(g)} + O_{(g)} -> 2O_{2(g)}}\]

Options

  • 3 and 1

  • 3 and 2

  • 4 and 2

  • 2 and 2

MCQ

Solution

2 and 2

Explanation:

\[\ce{O_{3(g)} + O_{(g)} -> 2O_{2(g)}}\]

  1. rate = k[O3][O]
    ∴ Order of reaction = 2
  2. Molecularity (No. of reactant molecules taking part in reaction) = 2
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Rate of Reaction and Reactant Concentration
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